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(4.9(x^2))-24.5x+21=0
We add all the numbers together, and all the variables
-24.5x+(4.9x^2)+21=0
We get rid of parentheses
4.9x^2-24.5x+21=0
a = 4.9; b = -24.5; c = +21;
Δ = b2-4ac
Δ = -24.52-4·4.9·21
Δ = 188.65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24.5)-\sqrt{188.65}}{2*4.9}=\frac{24.5-\sqrt{188.65}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24.5)+\sqrt{188.65}}{2*4.9}=\frac{24.5+\sqrt{188.65}}{9.8} $
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